ID: A 2 6 ANS: Parallelogram ANDR with AW and DE bisecting NWD and REA at points W and E (Given).AN ≅RD, AR ≅DN (Opposite sides of a parallelogram are congruent).AE = 1 2 AR, WD = 1 2 DN, so AE ≅WD (Definition of bisect and division property of equality). Proof: (i) In ∆ADC and ∆CBA, Finally, since

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